Asked by Austin
express (1/x-2)-(2/x+5)=(3/x+1) in the form of ax^2+bx=0
Answers
Answered by
Reiny
I suspect you are looking at
1/(x-2) - 2/(x+5) = 3/(x+1)
The LCD is (x-2)(x+5)(x+1) , so multiply each term by that to get
(x+5)(x+1) - 2(x-2)(x+1) = 3(x+5)(x-2)
now, carefully expand this, collect all like terms and express the
equation if the required form.
1/(x-2) - 2/(x+5) = 3/(x+1)
The LCD is (x-2)(x+5)(x+1) , so multiply each term by that to get
(x+5)(x+1) - 2(x-2)(x+1) = 3(x+5)(x-2)
now, carefully expand this, collect all like terms and express the
equation if the required form.
Answered by
Austin
hey can u please expand it and symplify coz am stack plz help i dnt knw it, just show me and get the answer