Question
Which would result in 1? Zero power of
(-2.97^0)
13 - 7.42^0
5^0 + 9^0
(-2.97^0)
13 - 7.42^0
5^0 + 9^0
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To analyze which of the given expressions results in 1, we can evaluate them one by one while keeping in mind the property that any non-zero number raised to the power of 0 equals 1.
1. **For \((-2.97^0)\)**:
\(-2.97^0 = 1\) (since \(-2.97\) is non-zero).
2. **For \(13 - 7.42^0\)**:
\(7.42^0 = 1\) (since \(7.42\) is non-zero),
thus, \(13 - 7.42^0 = 13 - 1 = 12\).
3. **For \(5^0 + 9^0\)**:
\(5^0 = 1\) and \(9^0 = 1\),
therefore, \(5^0 + 9^0 = 1 + 1 = 2\).
Among these evaluations, the only expression that results in 1 is:
\(-2.97^0\).
Thus, the answer is \(-2.97^0\).
1. **For \((-2.97^0)\)**:
\(-2.97^0 = 1\) (since \(-2.97\) is non-zero).
2. **For \(13 - 7.42^0\)**:
\(7.42^0 = 1\) (since \(7.42\) is non-zero),
thus, \(13 - 7.42^0 = 13 - 1 = 12\).
3. **For \(5^0 + 9^0\)**:
\(5^0 = 1\) and \(9^0 = 1\),
therefore, \(5^0 + 9^0 = 1 + 1 = 2\).
Among these evaluations, the only expression that results in 1 is:
\(-2.97^0\).
Thus, the answer is \(-2.97^0\).
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