Instructions

This assignment will assess your ability to calculate the mean, median, mode, variance, and standard deviation of a set of data.

The weights of the starting lineup of a football team are as follows (in pounds)
Also, can you add all these numbers together, please?
218 234 210 261 265 175 191 308
253 295 253 220 234 232 189 208
190 202 159 304 275 305 308 295

Open a new word processing document and complete the following. Be sure to show all work.

Part 1:

Calculate the mean of the weights.

Part 2:

What is the median of the weights?

Part 3:

Identify the mode of the weights.

Part 4:

Calculate the range of the weights.

Part 5:

Calculate the variance of the data.

Part 6:

Calculate the standard deviation of the data.

1 answer

Sure! Below are the calculations for mean, median, mode, variance, and standard deviation, as well as the sum of the weights provided.

Given Data:

Weights (in pounds): 218, 234, 210, 261, 265, 175, 191, 308, 253, 295, 253, 220, 234, 232, 189, 208, 190, 202, 159, 304, 275, 305, 308, 295.

Part 1: Calculate the Mean

Mean = (Sum of all data points) / (Number of data points)

  1. Sum of Weights: \[ 218 + 234 + 210 + 261 + 265 + 175 + 191 + 308 + 253 + 295 + 253 + 220 + 234 + 232 + 189 + 208 + 190 + 202 + 159 + 304 + 275 + 305 + 308 + 295 = 5844 \]

  2. Number of Data Points: 24

  3. Mean Calculation: \[ \text{Mean} = \frac{5844}{24} = 243.5 \]

Part 2: What is the Median?

To find the median, we need to order the data from least to greatest and find the middle value.

Ordered Weights: 159, 175, 189, 190, 191, 202, 208, 210, 218, 220, 232, 234, 234, 253, 253, 261, 265, 275, 295, 295, 304, 305, 308, 308.

Number of Data Points: 24 (even), so the median is the average of the 12th and 13th values.

Median Calculation: \[ \text{12th value} = 234, \text{13th value} = 253 \] \[ \text{Median} = \frac{234 + 253}{2} = \frac{487}{2} = 243.5 \]

Part 3: Identify the Mode

The mode is the number that appears most frequently in the data set.

From the data:

  • 234: 2 times
  • 253: 2 times
  • All other weights appear only once.

Modes: 234 and 253 (Bimodal).

Part 4: Calculate the Range

Range = (Maximum value) - (Minimum value)

  • Maximum = 308
  • Minimum = 159

\[ \text{Range} = 308 - 159 = 149 \]

Part 5: Calculate the Variance

  1. Mean = 243.5 (from Part 1).

  2. Calculate the squared deviations from the mean: \[ \text{Variance} = \frac{\sum (x_i - \text{Mean})^2}{N} \] Where \(x_i\) are the weights and \(N\) is the number of weights.

    Calculating each value squared deviation: \[ (218 - 243.5)^2 = 650.25 \ (234 - 243.5)^2 = 90.25 \ (210 - 243.5)^2 = 1130.25 \ (261 - 243.5)^2 = 306.25 \ (265 - 243.5)^2 = 462.25 \ (175 - 243.5)^2 = 4628.25 \ (191 - 243.5)^2 = 2760.25 \ (308 - 243.5)^2 = 4190.25 \ (253 - 243.5)^2 = 90.25 \ (295 - 243.5)^2 = 2656.25 \ (253 - 243.5)^2 = 90.25 \ (220 - 243.5)^2 = 552.25 \ (234 - 243.5)^2 = 90.25 \ (232 - 243.5)^2 = 132.25 \ (189 - 243.5)^2 = 3020.25 \ (208 - 243.5)^2 = 1240.25 \ (190 - 243.5)^2 = 2880.25 \ (202 - 243.5)^2 = 1690.25 \ (159 - 243.5)^2 = 7116.25 \ (304 - 243.5)^2 = 3660.25 \ (275 - 243.5)^2 = 992.25 \ (305 - 243.5)^2 = 3840.25 \ (308 - 243.5)^2 = 4190.25 \ (295 - 243.5)^2 = 2656.25 \]

Total of squared deviations: \[ 650.25 + 90.25 + 1130.25 + 306.25 + 462.25 + 4628.25 + 2760.25 + 4190.25 + 90.25 + 2656.25 + 90.25 + 552.25 + 90.25 + 132.25 + 3020.25 + 1240.25 + 2880.25 + 1690.25 + 7116.25 + 3660.25 + 992.25 + 3840.25 + 4190.25 + 2656.25 = 30783 \]

Now, divide by the number of data points: \[ \text{Variance} = \frac{30783}{24} \approx 1282.625 \]

Part 6: Calculate the Standard Deviation

Standard deviation is the square root of the variance. \[ \text{Standard Deviation} = \sqrt{1282.625} \approx 35.8 \]

Summary of Results:

  • Sum of Weights: 5844
  • Mean: 243.5
  • Median: 243.5
  • Mode: 234, 253
  • Range: 149
  • Variance: 1282.63
  • Standard Deviation: 35.8

You can now format this information into your word processing document. If you need any further assistance or clarification, let me know!