This assignment will assess your ability to calculate the mean, median, mode, variance, and standard deviation of a set of data.

The weights of the starting lineup of a football team are as follows (in pounds)

218 234 210 261 265 175 191 308
253 295 253 220 234 232 189 208
190 202 159 304 275 305 308 295
Make sure you show all work.

Part 1:
Calculate the mean of the weights.

Part 2:
What is the median of the weights?

Part 3:
Identify the mode of the weights.

Part 4:
Calculate the range of the weights.

Part 5:
Calculate the variance of the data.

Part 6:
Calculate the standard deviation of the data.

(Requirements: The mean, median, mode, and range calculations contain no errors.The calculation of the variance contains no errors.The calculation of the standard deviation contains no errors.)

1 answer

Let's start with the data given:

Weights (in pounds): \[ 218, 234, 210, 261, 265, 175, 191, 308, 253, 295, 253, 220, 234, 232, 189, 208, 190, 202, 159, 304, 275, 305, 308, 295 \]

Part 1: Calculate the mean of the weights.

To find the mean, sum all weights and divide by the number of weights.

  1. Sum of weights: \[ 218 + 234 + 210 + 261 + 265 + 175 + 191 + 308 + 253 + 295 + 253 + 220 + 234 + 232 + 189 + 208 + 190 + 202 + 159 + 304 + 275 + 305 + 308 + 295 = 6095 \]

  2. Number of weights: There are 24 weights.

  3. Mean: \[ \text{Mean} = \frac{\text{Sum of weights}}{\text{Number of weights}} = \frac{6095}{24} \approx 254.79 \]

Part 2: What is the median of the weights?

To find the median, arrange the weights in ascending order and find the middle value:

  1. Sorted weights: \[ 159, 175, 189, 190, 191, 202, 208, 210, 218, 220, 232, 234, 234, 253, 253, 261, 265, 275, 295, 295, 304, 305, 308, 308 \]

  2. Finding the median: Since there are 24 weights (an even number), the median is the average of the 12th and 13th values in the sorted list.

    12th value = 234
    13th value = 253

    \[ \text{Median} = \frac{234 + 253}{2} = \frac{487}{2} = 243.5 \]

Part 3: Identify the mode of the weights.

The mode is the value that appears most frequently in the data set.

  • From the sorted weights:
    • 234 appears 2 times
    • 253 appears 2 times

Since both 234 and 253 appear twice and are the most frequent, the data is bimodal.

Thus, the modes are 234 and 253.

Part 4: Calculate the range of the weights.

The range is the difference between the maximum and minimum values in the dataset.

  1. Maximum weight: 308
  2. Minimum weight: 159

\[ \text{Range} = \text{Maximum} - \text{Minimum} = 308 - 159 = 149 \]

Part 5: Calculate the variance of the data.

Variance is calculated using the formula: \[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{N} \] where \(x_i\) are the data points, \(\mu\) is the mean, and \(N\) is the number of data points.

  1. Find the deviations from the mean: \[ \mu \approx 254.79 \]

  2. Calculate each squared deviation: \[ (218-254.79)^2, (234-254.79)^2, (210-254.79)^2, \ldots, (295-254.79)^2 \] Calculating each deviation:

  • \( (218 - 254.79)^2 \approx 1310.5841 \)
  • \( (234 - 254.79)^2 \approx 430.9441 \)
  • \( (210 - 254.79)^2 \approx 1986.4641 \)
  • \( (261 - 254.79)^2 \approx 38.0641 \)
  • \( (265 - 254.79)^2 \approx 102.4641 \)
  • \( (175 - 254.79)^2 \approx 6296.9441 \)
  • \( (191 - 254.79)^2 \approx 4041.0641 \)
  • \( (308 - 254.79)^2 \approx 2850.6241 \)
  • \( (253 - 254.79)^2 \approx 3.2041 \)
  • \( (295 - 254.79)^2 \approx 1603.4641 \)
  • \( (253 - 254.79)^2 \approx 3.2041 \)
  • \( (220 - 254.79)^2 \approx 1197.0641 \)
  • \( (234 - 254.79)^2 \approx 430.9441 \)
  • \( (232 - 254.79)^2 \approx 525.0641 \)
  • \( (189 - 254.79)^2 \approx 4396.4641 \)
  • \( (208 - 254.79)^2 \approx 2209.0641 \)
  • \( (190 - 254.79)^2 \approx 4134.6241 \)
  • \( (202 - 254.79)^2 \approx 2793.6241 \)
  • \( (159 - 254.79)^2 \approx 9226.9441 \)
  • \( (304 - 254.79)^2 \approx 2453.1841 \)
  • \( (275 - 254.79)^2 \approx 408.0641 \)
  • \( (305 - 254.79)^2 \approx 2500.0641 \)
  • \( (308 - 254.79)^2 \approx 2850.6241 \)
  • \( (295 - 254.79)^2 \approx 1603.4641 \)
  1. Total of squared deviations: \[ \text{Total} \approx 19581.25 \]

  2. Variance: \[ \sigma^2 = \frac{19581.25}{24} \approx 815.094 \]

Part 6: Calculate the standard deviation of the data.

Standard deviation is the square root of the variance.

\[ \sigma \approx \sqrt{815.094} \approx 28.57 \]

Finally, here are all calculated values for reference:

  • Mean: \( \approx 254.79 \)
  • Median: \( 243.5 \)
  • Mode: \( 234, 253 \)
  • Range: \( 149 \)
  • Variance: \( \approx 815.094 \)
  • Standard Deviation: \( \approx 28.57 \)