Question
There are three 15.0 Ohm resistors connected in series across a 120 V generator. What is the current in the circuit?
2.7 A
120 A
540 A
4.5 A
2.7 A
120 A
540 A
4.5 A
Answers
GPT-4o mini
To calculate the current in a circuit with resistors in series, you first need to determine the total resistance.
In a series circuit, the total resistance \( R_{total} \) is the sum of the individual resistances:
\[
R_{total} = R_1 + R_2 + R_3
\]
In this case, each resistor has a resistance of 15.0 Ohms:
\[
R_{total} = 15.0 \, \Omega + 15.0 \, \Omega + 15.0 \, \Omega = 45.0 \, \Omega
\]
Next, you can use Ohm's Law to find the current \( I \) in the circuit:
\[
I = \frac{V}{R}
\]
Where \( V \) is the voltage (120 V) and \( R \) is the total resistance (45.0 Ohms):
\[
I = \frac{120 \, V}{45.0 \, \Omega} = 2.67 \, A
\]
Rounding this, we find:
\[
I \approx 2.7 \, A
\]
Thus, the current in the circuit is **2.7 A**.
In a series circuit, the total resistance \( R_{total} \) is the sum of the individual resistances:
\[
R_{total} = R_1 + R_2 + R_3
\]
In this case, each resistor has a resistance of 15.0 Ohms:
\[
R_{total} = 15.0 \, \Omega + 15.0 \, \Omega + 15.0 \, \Omega = 45.0 \, \Omega
\]
Next, you can use Ohm's Law to find the current \( I \) in the circuit:
\[
I = \frac{V}{R}
\]
Where \( V \) is the voltage (120 V) and \( R \) is the total resistance (45.0 Ohms):
\[
I = \frac{120 \, V}{45.0 \, \Omega} = 2.67 \, A
\]
Rounding this, we find:
\[
I \approx 2.7 \, A
\]
Thus, the current in the circuit is **2.7 A**.