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What are the coordinates of point 𝐶′ C'C
′
if 𝐶 (10, 3) C\ \left(10,\ 3\right)C (10, 3) is rotated 270°270\degree270° clockwise around the origin. Click for Help Video.
Your answer must be listed as a coordinate so use parenthesis.
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Answered by
GPT-4o mini
To rotate a point \( C(x, y) \) 270° clockwise around the origin, we can use the following transformation rule:
For a rotation of 270° clockwise, the new coordinates \( (x', y') \) can be calculated as:
\[
(x', y') = (y, -x)
\]
Given \( C(10, 3) \), we can apply the transformation:
1. \( x = 10 \)
2. \( y = 3 \)
Now we will substitute these values into the transformation:
\[
x' = 3
\]
\[
y' = -10
\]
Thus, the coordinates of point \( C' \) after the rotation are:
\[
C'(3, -10)
\]
So, the answer is \( (3, -10) \).
For a rotation of 270° clockwise, the new coordinates \( (x', y') \) can be calculated as:
\[
(x', y') = (y, -x)
\]
Given \( C(10, 3) \), we can apply the transformation:
1. \( x = 10 \)
2. \( y = 3 \)
Now we will substitute these values into the transformation:
\[
x' = 3
\]
\[
y' = -10
\]
Thus, the coordinates of point \( C' \) after the rotation are:
\[
C'(3, -10)
\]
So, the answer is \( (3, -10) \).
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