Asked by Jonathan
                Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle or a
parallelogram. Then find the area of the quadrilateral.
E(–7, –1), F(2, –1), G(–4, –8), H(5, –8)
            
        parallelogram. Then find the area of the quadrilateral.
E(–7, –1), F(2, –1), G(–4, –8), H(5, –8)
Answers
                    Answered by
            Damon
            
    draw it
the top is at -1
the bottom is at - 8
so it is 7 somethings high (question written by mathematician and they do not do units)
the top runs from -7 to +2 so is 9 somethings long
the bottom runs from -4 to +5 so is also 9 somethings long
the top starts 3 somethings to the left of the bottom
clearly it is a parallelogram
area = height * base = 7 * 9 = 63 somethings^2
    
the top is at -1
the bottom is at - 8
so it is 7 somethings high (question written by mathematician and they do not do units)
the top runs from -7 to +2 so is 9 somethings long
the bottom runs from -4 to +5 so is also 9 somethings long
the top starts 3 somethings to the left of the bottom
clearly it is a parallelogram
area = height * base = 7 * 9 = 63 somethings^2
                    Answered by
            Henry
            
    W = 2 - (-7) = 9.
L = 5 - (-4) = 9.
It is a square.
Area = 9 * 9 = 81 Square units.
    
L = 5 - (-4) = 9.
It is a square.
Area = 9 * 9 = 81 Square units.
                    Answered by
            Damon - not square
            
    left and right slope
    
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