Asked by Esther
What are the coordinates of the hole in the graph of the function f(x) ?
f(x)=x^2−9/x−3
f(x)=x^2−9/x−3
Answers
Answered by
scott
f(x) = [(x + 3)(x - 3)] / (x - 3)
when x = 3, there is a zero in both the numerator and denominator (hole)
find f(3) to get the coordinates
when x = 3, there is a zero in both the numerator and denominator (hole)
find f(3) to get the coordinates
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