Asked by Vince
Mary's age is 2/3 that of peter's. Two years ago Mary's age was 1/2 of what Peter's age will be in 5 year's time. How old is peter now?
Answers
Answered by
MathMate
Let P=peter's age, and
M=Mary's age.
M=(2/3)P.... (1)
Two years ago, Mary's age was M-2, and it was what Peter's age <i>will</i> be in 5 years time (P+5)/2
Therefore
M-2 = (P+5)/2
Substitute M from (1)
(2/3)P-2 = (P+5)/2
Solve for P to get P=27, and M=18
M=Mary's age.
M=(2/3)P.... (1)
Two years ago, Mary's age was M-2, and it was what Peter's age <i>will</i> be in 5 years time (P+5)/2
Therefore
M-2 = (P+5)/2
Substitute M from (1)
(2/3)P-2 = (P+5)/2
Solve for P to get P=27, and M=18
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