In a fixed volume container, 610^23 molecules of a gas exert a pressure of 12 N/m^2. If 1210^23 molecules of gas were added to the container, what would the pressure become?

PV=nRT

P=pressure in atm
V=volume in L
T=absolute (kelvin) temperature
R=0.082 L atm/mole K
n=number of moles

***the answer is 36 N/m^2. I don't know how to get this answer. Thank you for the help!

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In a fixed volume container, 610^23 molecules of a gas exert a pressure of 12 N/m^2. If 1210^23 molecules of gas were added to the container, what would the pressure become?