Asked by Mike
In a fixed volume container, 6*10^23 molecules of a gas exert a pressure of 12 N/m^2. If 12*10^23 molecules of gas were added to the container, what would the pressure become?
PV=nRT
P=pressure in atm
V=volume in L
T=absolute (kelvin) temperature
R=0.082 L atm/mole K
n=number of moles
***the answer is 36 N/m^2. I don't know how to get this answer. Thank you for the help!
PV=nRT
P=pressure in atm
V=volume in L
T=absolute (kelvin) temperature
R=0.082 L atm/mole K
n=number of moles
***the answer is 36 N/m^2. I don't know how to get this answer. Thank you for the help!
Answers
Answered by
Anonymous
36
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.