A container having a volume of 1 m3

holds
90 mol of helium gas at 176

C.
Boltzmann’s constant is 1.38 × 10
−23
J/K.
Assuming the helium behaves like an ideal
gas, what is the average kinetic energy per
molecule?
Answer in units of J

User Icon for bob bob answered
10 years ago

32

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the average kinetic energy per molecule of helium gas, we can use the equation:

Average kinetic energy per molecule = (3/2) * k * T

where:
- k is Boltzmann's constant (1.38 × 10^-23 J/K)
- T is the temperature in Kelvin

First, we need to convert the given temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15
T(K) = 176 °C + 273.15
T(K) = 449.15 K

Now that we have the temperature in Kelvin, we can substitute the values into the equation:

Average kinetic energy per molecule = (3/2) * (1.38 × 10^-23 J/K) * 449.15 K

Calculating the expression:

Average kinetic energy per molecule = (3/2) * (1.38 × 10^-23 J/K) * 449.15 K
Average kinetic energy per molecule ≈ 9.19 × 10^-21 J

Therefore, the average kinetic energy per molecule of helium gas is approximately 9.19 × 10^-21 J.