Asked by Maria
solve one ninth = 27^3x-5.
Answers
Answered by
Reiny
27^(3x-5) = 1/9
(3^3)^(3x-5) = 3^(-2)
3^(9x-15) = 3^(-2)
9x - 15 = -2
9x = 13
x = 13/9
(3^3)^(3x-5) = 3^(-2)
3^(9x-15) = 3^(-2)
9x - 15 = -2
9x = 13
x = 13/9
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