Question
solve one ninth = 27^3x-5.
Answers
Reiny
27^(3x-5) = 1/9
(3^3)^(3x-5) = 3^(-2)
3^(9x-15) = 3^(-2)
9x - 15 = -2
9x = 13
x = 13/9
(3^3)^(3x-5) = 3^(-2)
3^(9x-15) = 3^(-2)
9x - 15 = -2
9x = 13
x = 13/9