Asked by Matt

The second and ninth terms of an arithmetic sequence are 2 and 30 respectively. What is the fiftieth term.
Answered by Reiny
t2 = a + d = 2
t9 = a + 8d = 30
subtract them
7x = 28
d = 4

in a+d=2
a + 4 = 2
a = -2

t15 = a + 14d = -2 + 14(4) = 54
Answered by Matt
It is the fiftieth term not the fifteenth so would it be t50=a+49d
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