Question
Ice floats with one ninth of its volume above water. What is the relative density of ice?
Answers
Henry
9/9 - 1/9 = 8/9 of its' volume below water.
Dw = 1 g/cm^3.
Vb = Di/Dw * Vi.
8/9 = Di/1 * 1, Di = 0.889 g/cm^3.
Dw = 1 g/cm^3.
Vb = Di/Dw * Vi.
8/9 = Di/1 * 1, Di = 0.889 g/cm^3.