Asked by Betty
What is the ninth term of the following geometric sequence?
a4=27
a7=64
a9=
a4=27
a7=64
a9=
Answers
Answered by
Reiny
a+3d = 27
a+6d = 64
subtract them
3d = 37
d = 37/3
a + 3(37/3) = 27
a = -10
term(9) = a+8d
= -10 + 8(37/3) = 266/3
check:
term(4) = a+3d = -10 + 3(37/3) = 27
term(7) = a+6d = -10 + 6(37/3) = 64
a+6d = 64
subtract them
3d = 37
d = 37/3
a + 3(37/3) = 27
a = -10
term(9) = a+8d
= -10 + 8(37/3) = 266/3
check:
term(4) = a+3d = -10 + 3(37/3) = 27
term(7) = a+6d = -10 + 6(37/3) = 64
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