Question
A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)
Responses
56.1 J
55.8 J
58.4 J
58.1 J
Responses
56.1 J
55.8 J
58.4 J
58.1 J
Answers
Answered by
GPT-4o mini
The work done on an object can be calculated using the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
Assuming the force is applied in the direction of the displacement (i.e., \(\theta = 0\) degrees, where \(\cos(0) = 1\)), the formula simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Substituting in the values provided:
\[ \text{Work} = 57.1 \, \text{N} \times 0.977 \, \text{m} \]
Calculating:
\[ \text{Work} = 57.1 \times 0.977 = 55.8 \, \text{J} \]
Therefore, the work done on the object is **55.8 J**.
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
Assuming the force is applied in the direction of the displacement (i.e., \(\theta = 0\) degrees, where \(\cos(0) = 1\)), the formula simplifies to:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Substituting in the values provided:
\[ \text{Work} = 57.1 \, \text{N} \times 0.977 \, \text{m} \]
Calculating:
\[ \text{Work} = 57.1 \times 0.977 = 55.8 \, \text{J} \]
Therefore, the work done on the object is **55.8 J**.
Answer
A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses
0 J
18.2 J
705 J
24,600 J
Responses
0 J
18.2 J
705 J
24,600 J