Asked by Anonymous

A force of 30 Newtons is used to elongate a spring a distance of 9 cm. A) What was the coefficient of elasticity of the spring? B) How much work must be done to elongate the spring a distance of 18 cm.?

Answers

Answered by Henry
A. k = F/d = 30N./9cm = 3.33 N/cm.
B. F = 3.33N/cm * 18cm = 60 N,
Work = F * d = 60 * 18 Joules.
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