Asked by Anonymous
A force of 30 Newtons is used to elongate a spring a distance of 9 cm. A) What was the coefficient of elasticity of the spring? B) How much work must be done to elongate the spring a distance of 18 cm.?
Answers
Answered by
Henry
A. k = F/d = 30N./9cm = 3.33 N/cm.
B. F = 3.33N/cm * 18cm = 60 N,
Work = F * d = 60 * 18 Joules.
B. F = 3.33N/cm * 18cm = 60 N,
Work = F * d = 60 * 18 Joules.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.