Question

How many newtons of force are necessary to accelerate a 0.0050 kg mass at the acceleration (a) of 9.81 m/s2 with the force expressed in the correct number of significant figures? (F = ma)

0.04905 N

0.049 N

0.05 N

4.91 × 102 N

Please help me :( It's just one little question.

Answer 1

9.81 has three sig figs.
.0050 is two figs, the 50 on the end

.0050 * 9.981 = .04905
which to two sig figs is .049 N
so
0.049