Question
What is the smallest degree a polynomial with five relative minima and six relative maxima could have?
A. 30
B. 12
C. 11
D. 6
A. 30
B. 12
C. 11
D. 6
Answers
Answered by
GPT-4o mini
To find the smallest degree of a polynomial that can have a given number of relative minima and maxima, we can use the relationship between the number of local extrema (minima and maxima) and the degree of the polynomial.
Let \( m \) represent the number of relative minima and \( M \) represent the number of relative maxima. The total number of relative extrema is given by:
\[
E = m + M
\]
In this case, we have:
\[
m = 5 \quad \text{and} \quad M = 6
\]
Thus, the total number of relative extrema is:
\[
E = 5 + 6 = 11
\]
According to the properties of polynomials, a polynomial of degree \( n \) can have at most \( n - 1 \) relative extrema. Therefore, to accommodate \( 11 \) relative extrema, the degree \( n \) of the polynomial must satisfy:
\[
n - 1 \geq E
\]
Substituting for \( E \):
\[
n - 1 \geq 11
\]
Solving for \( n \):
\[
n \geq 12
\]
This means that the smallest degree \( n \) is \( 12 \).
Thus, the answer is:
\[
\boxed{12}
\]
Let \( m \) represent the number of relative minima and \( M \) represent the number of relative maxima. The total number of relative extrema is given by:
\[
E = m + M
\]
In this case, we have:
\[
m = 5 \quad \text{and} \quad M = 6
\]
Thus, the total number of relative extrema is:
\[
E = 5 + 6 = 11
\]
According to the properties of polynomials, a polynomial of degree \( n \) can have at most \( n - 1 \) relative extrema. Therefore, to accommodate \( 11 \) relative extrema, the degree \( n \) of the polynomial must satisfy:
\[
n - 1 \geq E
\]
Substituting for \( E \):
\[
n - 1 \geq 11
\]
Solving for \( n \):
\[
n \geq 12
\]
This means that the smallest degree \( n \) is \( 12 \).
Thus, the answer is:
\[
\boxed{12}
\]