Asked by thmas

If n=-8, what is the smallest perfect square that is greater than n^2 ?

a. 64
b. -64
c. 81
d. -81
e. 16

please answer and explain
Answered by PsyDAG
81 > n^2 = (-8)^2
Answered by thmas
a. 64
Answered by thmas
i use (-8)x (-8) = 64

I use calculator X^2

-8^2 = -64
Answered by Steve
However, they are asking for the smallest square greater than 64, which is 81.

Note that
-8^2 = -(8^2) = -64
(-8)^2 = +64
There are no AI answers yet. The ability to request AI answers is coming soon!