Asked by Madison Joe
What is the smallest of three consecutive integers if
the sum of the smaller two integers is equal to 177 less than four times the largest?
Note: Consecutive integers are integers that come one after the other. For example: -3, -2 and -1 or 14, 15 and 16. Therefore, if the first number is x, the second is x + 1 and the third is x + 2. Each time we add one to the previous integer to get the next consecutive integer.
the sum of the smaller two integers is equal to 177 less than four times the largest?
Note: Consecutive integers are integers that come one after the other. For example: -3, -2 and -1 or 14, 15 and 16. Therefore, if the first number is x, the second is x + 1 and the third is x + 2. Each time we add one to the previous integer to get the next consecutive integer.
Answers
Answered by
Reiny
smallest number ---- x
middle number ------ x+1
larger number --------x+2
x + x+1 = 4(x+2) - 177
2x+1 = 4x+8-117
-2x = -110
x = 55
the smallest is 55
middle number ------ x+1
larger number --------x+2
x + x+1 = 4(x+2) - 177
2x+1 = 4x+8-117
-2x = -110
x = 55
the smallest is 55
Answered by
Joshua pouncy
i tried 55 and i got it wrong
Answered by
Joshua pouncy
Reiny me and madison don't understand this we got it wrong when we tried 55
Answered by
Madison Joe
I even double checked and its wrong i don't know why?
Answered by
Ms. Sue
Amy/Brianna/ Joshua/Madison -- please use the same name for your posts.
Answered by
Ms. Sue
Correction of subject
Answered by
Reiny
According to my solution the 3 numbers are
55, 56, and 57
sum of the first two = 55+56 = 111
117 less than 4 times the larger = 4(57) - 117
= 111
Well, what do you know, it works
55, 56, and 57
sum of the first two = 55+56 = 111
117 less than 4 times the larger = 4(57) - 117
= 111
Well, what do you know, it works
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