Asked by joe s
smallest degree that satisfies 2cos^2x-3cosx=2
Answers
Answered by
Reiny
2cos^2x-3cosx=2
2cos^2x - 3cosx - 2 = 0
(2cosx + 1)(cosx - 2) = 0
cosx = -1/2 or cosx = 2, the last part is not possible
cosx = -1/2, so the smallest angle is in quadrant II
x = 120° or 2π/3 rads , assuming you wanted the smallest positive angle
2cos^2x - 3cosx - 2 = 0
(2cosx + 1)(cosx - 2) = 0
cosx = -1/2 or cosx = 2, the last part is not possible
cosx = -1/2, so the smallest angle is in quadrant II
x = 120° or 2π/3 rads , assuming you wanted the smallest positive angle
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.