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Find the solutions to the equation cos2x=sinx and 2cos^2x-3cosx-3=0
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Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).
8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
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Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
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Find all solutions to the equation in the interval [0, 2pi)
cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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