Question

Use the equation of motion to answer the question.

x=x0 +v0t + 12at2

An object has a starting position of X = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?

(1 point)
Responses

18 m
18 m

11 m
11 m

9 m
9 m

5.5 m

Answer 1

To find the final position of the object after 2 seconds using the equation of motion, we can plug in the values given:

- \(x_0 = 2\) m (starting position)
- \(v_0 = 4.5\) m/s (starting velocity)
- \(a = 0\) m/s² (no acceleration)
- \(t = 2\) s (time)

The equation becomes:

\[
x = x_0 + v_0 t + \frac{1}{2} a t^2
\]

Substituting in the known values:

\[
x = 2 + 4.5 \times 2 + \frac{1}{2} \times 0 \times (2)^2
\]

Calculating step by step:

1. Calculate \(4.5 \times 2 = 9\).
2. Since the acceleration is 0, \(\frac{1}{2} \times 0 \times (2)^2 = 0\).
3. Now sum it all up:
\[
x = 2 + 9 + 0 = 11 \, \text{m}
\]

So the final position of the object after 2 seconds is **11 m**. Thus, the correct response is:

**11 m**.