Asked by Jason
The equation of motion for an oscillator is given by y= (0.200cm)sin (140t). What are the 1)alplitude, 2)period, and 3) frequency of this motion?
Answers
Answered by
drwls
y = (Amplitude)*sin(2 pi f t), therefore
Amplitude = 0.200 cm
Frequency (f) = 140/(2 pi) = 22.3 Hz
Period P = 1/f = 0.0449 s
Amplitude = 0.200 cm
Frequency (f) = 140/(2 pi) = 22.3 Hz
Period P = 1/f = 0.0449 s
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