well, let's set the velocity equal to zero ...
3t^2 - 12 = 0
3t^2 = 12
t^2 = 4
t = ± 2, but t ≥0
so the velocity is zero when t = 2
so what is the acceleration when t = 2 ??
The equation of motion of a particle is
s = t3 − 12t, where s is in meters and t is in seconds.
For the velocity function, I got v(t)=3t^2-12 and for acceleration, a(t)=6t. The final question is: Find the acceleration when the velocity is 0. How do I do that?
2 answers
s=t^3-12t
v=ds/dt=3t^2-12
a=dv/dt=6t
when is velocity 0?
v=3t^2-12=0
t^2=4
t=2 and at t=2, a=6*2=12
v=ds/dt=3t^2-12
a=dv/dt=6t
when is velocity 0?
v=3t^2-12=0
t^2=4
t=2 and at t=2, a=6*2=12
0 answers