What is the output of calling n2.calculate()?

Question

class Addition:
def __init__(self, f, s):
self.first = f
self.second = s

def calculate(self):
self.answer = self.first + self.second
print("Addition of two numbers = " + str(self.answer))

n1 = Addition(1000, 2000)
n2 = Addition(3000,1000)
n3 = Addition(2000, 4000)
n4 = Addition(3000,4000)

(1 point)
Responses

Addition of two numbers = 3000
Addition of two numbers = 3000

Addition of two numbers = 4000
Addition of two numbers = 4000

Addition of two numbers = 6000
Addition of two numbers = 6000

Addition of two numbers = 7000

Answer 1

When you call n2.calculate(), it executes the calculate method of the Addition class for the instance n2, which was initialized with the values 3000 and 1000.

Here's how the execution of n2.calculate() proceeds:

1. The calculate method adds the two numbers stored in self.first and self.second (i.e., 3000 and 1000).
2. The result of the addition is 4000.
3. This result is then printed with the message: "Addition of two numbers = 4000".

Therefore, the output of calling n2.calculate() will be:

Addition of two numbers = 4000

This matches one of the provided responses:

Addition of two numbers = 4000