Question

What is the output of calling n2.calculate()?

class Addition:
def __init__(self, f, s):
self.first = f
self.second = s

def calculate(self):
self.answer = self.first + self.second
print("Addition of two numbers = " + str(self.answer))

n1 = Addition(1000, 2000)
n2 = Addition(3000,1000)
n3 = Addition(2000, 4000)
n4 = Addition(3000,4000)

(1 point)
Responses

Addition of two numbers = 3000
Addition of two numbers = 3000

Addition of two numbers = 4000
Addition of two numbers = 4000

Addition of two numbers = 6000
Addition of two numbers = 6000

Addition of two numbers = 7000

Answer 1

When you call `n2.calculate()`, it executes the `calculate` method of the `Addition` class for the instance `n2`, which was initialized with the values `3000` and `1000`.

Here's how the execution of `n2.calculate()` proceeds:

1. The `calculate` method adds the two numbers stored in `self.first` and `self.second` (i.e., `3000` and `1000`).
2. The result of the addition is `4000`.
3. This result is then printed with the message: "Addition of two numbers = 4000".

Therefore, the output of calling `n2.calculate()` will be:

```
Addition of two numbers = 4000
```

This matches one of the provided responses:

**Addition of two numbers = 4000**