Question

Basic Programming Unit Test 16 of 2616 of 26 Items Question What is the output of calling n2.calculate()? class Addition: def __init__(self, f, s): self.first = f self.second = s def calculate(self): self.answer = self.first + self.second print("Addition of two numbers = " + str(self.answer)) n1 = Addition(1000, 2000) n2 = Addition(3000,1000) n3 = Addition(2000, 4000) n4 = Addition(3000,4000) (1 point) Responses Addition of two numbers = 4000 Addition of two numbers = 4000 Addition of two numbers = 7000 Addition of two numbers = 7000 Addition of two numbers = 3000 Addition of two numbers = 3000 Addition of two numbers = 6000 Addition of two numbers = 6000 Skip to navigation page 1 of 1

Answer 1

To determine the output of calling `n2.calculate()`, we need to analyze the code provided.

The class `Addition` has an `__init__` method that initializes two instance variables, `first` and `second`, with the values provided as arguments. The `calculate` method calculates the sum of `first` and `second`, stores it in `self.answer`, and then prints it.

Here's a breakdown:

1. When `n2` is created with `n2 = Addition(3000, 1000)`, the instance variables are set as follows:
- `self.first` = 3000
- `self.second` = 1000

2. When `n2.calculate()` is called, the method calculates:
- `self.answer` = `self.first` + `self.second` = 3000 + 1000 = 4000

3. The print statement in the `calculate` method then outputs:
```
Addition of two numbers = 4000
```

So the output of calling `n2.calculate()` is:

```
Addition of two numbers = 4000
```

Therefore, the correct response is:
**Addition of two numbers = 4000**.