Question

What is the output of calling n2.calculate()?

class Addition:
def __init__(self, f, s):
self.first = f
self.second = s

def calculate(self):
self.answer = self.first + self.second
print("Addition of two numbers = " + str(self.answer))

n1 = Addition(1000, 2000)
n2 = Addition(3000,1000)
n3 = Addition(2000, 4000)
n4 = Addition(3000,4000)
(1 point)
Responses

Addition of two numbers = 6000
Addition of two numbers = 6000

Addition of two numbers = 7000
Addition of two numbers = 7000

Addition of two numbers = 3000
Addition of two numbers = 3000

Addition of two numbers = 4000

Answer 1

To determine the output of calling `n2.calculate()`, we will look at the attributes of the `n2` instance of the `Addition` class.

The `n2` object is created with the following parameters:
```python
n2 = Addition(3000, 1000)
```

In the `__init__` method, these values are assigned to `self.first` and `self.second`. Therefore:
- `self.first` = 3000
- `self.second` = 1000

When the `calculate` method is called on `n2`, it performs the following steps:
1. It calculates the sum of `self.first` and `self.second`:
```python
self.answer = self.first + self.second
```
This means:
```python
self.answer = 3000 + 1000 = 4000
```

2. It then prints the result:
```python
print("Addition of two numbers = " + str(self.answer))
```
This will output:
```
Addition of two numbers = 4000
```

Thus, the output of calling `n2.calculate()` will be:
```
Addition of two numbers = 4000
```