What is the output of calling n2.calculate()?

Question

class Addition:
def __init__(self, f, s):
self.first = f
self.second = s

def calculate(self):
self.answer = self.first + self.second
print("Addition of two numbers = " + str(self.answer))

n1 = Addition(1000, 2000)
n2 = Addition(3000,1000)
n3 = Addition(2000, 4000)
n4 = Addition(3000,4000)
(1 point)
Responses

Addition of two numbers = 6000
Addition of two numbers = 6000

Addition of two numbers = 7000
Addition of two numbers = 7000

Addition of two numbers = 3000
Addition of two numbers = 3000

Addition of two numbers = 4000

Answer 1

To determine the output of calling n2.calculate(), we will look at the attributes of the n2 instance of the Addition class.

The n2 object is created with the following parameters:

n2 = Addition(3000, 1000)

In the __init__ method, these values are assigned to self.first and self.second. Therefore:

• self.first = 3000
• self.second = 1000

When the calculate method is called on n2, it performs the following steps:

1. It calculates the sum of self.first and self.second:

   self.answer = self.first + self.second
   

   This means:

   self.answer = 3000 + 1000 = 4000
   

2. It then prints the result:

   print("Addition of two numbers = " + str(self.answer))
   

   This will output:

   Addition of two numbers = 4000
   

Thus, the output of calling n2.calculate() will be:

Addition of two numbers = 4000