Asked by Mike
A supersonic plane flies directly over you at 1.8 times the sound speed. You hear its sonic boom 20s later.
What is the plane's altitude, assuming a constant 340 sound speed?
What is the plane's altitude, assuming a constant 340 sound speed?
Answers
Answered by
bobpursley
height= velocity sound*time
Answered by
drwls
The angle that the bow shock wave makes with the velocity vector, and with the ground, is
A = sin^-1 (1/M) = 33.8 degrees.
The relationship between altitude h and sonic boom delay time t is:
h/(Vt) = tan A = 0.668
where V = airplane speed = M*Vsound = 612 m/s
Thus
h = 0.668 v t = 818 m
BobPursley's formula would result in
680 m.
The shock wave cone behind the airplane moves faster than the speed of sound.
A = sin^-1 (1/M) = 33.8 degrees.
The relationship between altitude h and sonic boom delay time t is:
h/(Vt) = tan A = 0.668
where V = airplane speed = M*Vsound = 612 m/s
Thus
h = 0.668 v t = 818 m
BobPursley's formula would result in
680 m.
The shock wave cone behind the airplane moves faster than the speed of sound.
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