Asked by Shalom
A plane flies from A and B,a distance of.a 120km on a bearing of 035°. If then changes direction and flies to C,a further distance of 200km on a bearing of 125°. Find: 1. The distance AC to nearest kin. 2. The bearing of C from A
Answers
Answered by
oobleck
Note that the course change was 90°. So,
#1. AC^2 = 120^2 + 200^2
#2. The bearing from A to C is θ+35° where tanθ = 200/120
#1. AC^2 = 120^2 + 200^2
#2. The bearing from A to C is θ+35° where tanθ = 200/120
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