I don't like any of the answers although 2.27 comes the closest.
Mg + 2HCl ==> H2 + MgCl2.
0.1 mol Mg (Mg is the limiting reagent) will produce 0.1 mol H2 so 0.1 x (22.4 L/mol) = 2.24 L.
Can someone check my answer please:
Magnesium metal(0.100 mol)and a volume of aqueous HCL that contains 0.500 mol are combined to react to completion. how many litres of hydrogen gas (measured at STP) are produced
choices:
4.42
11.1
22.7
2.27
5.53
I like 2.27...
Is this right??
thanks Andy
5 answers
I wonder what you have been taught about the molar volume of an ideal gas. I've always used 22.4 L/mol. But your answer implies that 22.7 is being used.
2.27 sounds the best option
It cant be 5.53 or 4.42 the maths don't add up!!!
So i agree thanks
It cant be 5.53 or 4.42 the maths don't add up!!!
So i agree thanks
Yes the text book says and I quote:
V=nRT/P=(1.000mol)(8.314kPa L/mol K)(273.15 K)/100kPa=22.71L
This is the molar volume of any ideal gas at STP.(if non-si units of atmospheres and the gas constant value of 0.08206 atm L/mol are used , the value is 22.41 L
Hope that helps...
Andy
V=nRT/P=(1.000mol)(8.314kPa L/mol K)(273.15 K)/100kPa=22.71L
This is the molar volume of any ideal gas at STP.(if non-si units of atmospheres and the gas constant value of 0.08206 atm L/mol are used , the value is 22.41 L
Hope that helps...
Andy
On this side of the pond, to use Dr Russ' favorite line, we use 22.4 L/mol. Thanks for the information. The difference is the 100 kPa vs 101.325 (1 atm).
4 answers