Question

Find the vertex of y^2 + 4y + 2x +10 = 0. Use completing the square to put the equation into standard form as your first step. Could you show me how to get the vertex? Thanks
y^2 + 4y <b>+ 4 - 4</b> + 2x + 10 = 0
(y+2)^2 + 6 = -2x
x = (-1/2)(y+2)^2 + 6

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