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Asked by April

Find the vertex

f(x)= x^2+6x+5
8 years ago

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Answered by Steve
as always, for y=ax^2+bx+c, the vertex is at

x = -b/2a = -3
f(-3) = -(b^2-4ac)/(4a) = -4
8 years ago
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Find the vertex

f(x)= x^2+6x+5

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