Question
Find the vertex
f(x)= x^2+6x+5
f(x)= x^2+6x+5
Answers
Steve
as always, for y=ax^2+bx+c, the vertex is at
x = -b/2a = -3
f(-3) = -(b^2-4ac)/(4a) = -4
x = -b/2a = -3
f(-3) = -(b^2-4ac)/(4a) = -4