Question
Find the vertex: -1/4x^2+9/5x+2
Answers
Damon
I assume you mean:
-x^2/4 + 9 x/5 + 2 = y
complete the square
first multiply by -4
x^2 - 36 x/5 - 8 = y
x^2 - 36 x/5 = y+8
x^2 - 36 x/5 + (18/5)^2 = y + 8 + 12.96
(x-18/5)^2 = y + 20.96
so vertex at
( 3.6 , -20.96)
-x^2/4 + 9 x/5 + 2 = y
complete the square
first multiply by -4
x^2 - 36 x/5 - 8 = y
x^2 - 36 x/5 = y+8
x^2 - 36 x/5 + (18/5)^2 = y + 8 + 12.96
(x-18/5)^2 = y + 20.96
so vertex at
( 3.6 , -20.96)