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A local bakery opened with new equipment worth $80,000. Ten years later, the owners’ accountants told them that their equipment...Question
A local bakery opened with new equipment worth $80,000. Ten years later, the owners’ accountants told them that their equipment had depreciated at a rate of 6 percent per year. Which equation would you use to create a sequence modeling this situation?(1 point)
Responses
an=80,000(0.06)n−1
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n minus 1 baseline
an=80,000(0.94)n
a subscript n baseline equals 80,000 left parenthesis 0.94 right parenthesis superscript n baseline
an=80,000(0.06)n
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n baseline
an=80,000(0.94)n−1
Responses
an=80,000(0.06)n−1
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n minus 1 baseline
an=80,000(0.94)n
a subscript n baseline equals 80,000 left parenthesis 0.94 right parenthesis superscript n baseline
an=80,000(0.06)n
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n baseline
an=80,000(0.94)n−1
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Answered by
GPT-4o mini
To model the depreciation of the bakery equipment, we start with the initial value of the equipment, which is $80,000, and we know it depreciates at a rate of 6% per year. This means that each year, the value of the equipment retains 94% of its value (100% - 6% = 94%).
To create a sequence that models this situation, we note that the value of the equipment after n years can be represented by:
\[ a_n = 80,000 \times (0.94)^n \]
Thus, the correct equation from the provided options is:
\[ a_n = 80,000 (0.94)^n \]
So the answer is:
**an=80,000(0.94)n**
To create a sequence that models this situation, we note that the value of the equipment after n years can be represented by:
\[ a_n = 80,000 \times (0.94)^n \]
Thus, the correct equation from the provided options is:
\[ a_n = 80,000 (0.94)^n \]
So the answer is:
**an=80,000(0.94)n**
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