Asked by Kim

What is the boiling point of each solution?

a).50mol glucose in 1000g H2O
b)1.50mol NaCl in 1000g H2O
Answered by DrBob222
molality = moles/kg
Solve for molality.

delta T = Kb*molality
Solve for delta T.
Add to normal boiling point.
Answered by meera
0.50mol NaCl in1000gH2o
Answered by breezy
a. a. (T-100°C)= 0.512°C /molal x 0.50 mol/ 1.00 kg
T=100°C + 0.256°C = 100.256°C