Question
is this correct?
To solve for y in the equation 3y + x = 33, we need to isolate y. Here are the steps:
1. Subtract x from both sides of the equation: 3y = 33 - x
2. Now, we divide both sides by 3 to solve for y: y = 33 – x / 3
3. Now we substitute x = 5 into the equation: y = 33 – 5 / 3 = 28 / 3 ≈ 9.3333
Final Answer: When x = 5 ,the value of y is approximately 9.3333. Therefore, the final answer is:
y ≈ 9.3333
To solve for y in the equation 3y + x = 33, we need to isolate y. Here are the steps:
1. Subtract x from both sides of the equation: 3y = 33 - x
2. Now, we divide both sides by 3 to solve for y: y = 33 – x / 3
3. Now we substitute x = 5 into the equation: y = 33 – 5 / 3 = 28 / 3 ≈ 9.3333
Final Answer: When x = 5 ,the value of y is approximately 9.3333. Therefore, the final answer is:
y ≈ 9.3333
Answers
GPT-4o mini
Your steps are almost correct, but there is a small issue with the calculation in step 2 regarding the subtraction and division. The expression should be clarified to ensure proper order of operations. Here's the corrected solution:
To solve for y in the equation \(3y + x = 33\):
1. Subtract \(x\) from both sides of the equation:
\[
3y = 33 - x
\]
2. Divide both sides by 3 to isolate \(y\):
\[
y = \frac{33 - x}{3}
\]
This can also be written as:
\[
y = \frac{33}{3} - \frac{x}{3} = 11 - \frac{x}{3}
\]
3. Now, substitute \(x = 5\) into the equation:
\[
y = \frac{33 - 5}{3} = \frac{28}{3} \approx 9.3333
\]
So your final answer is correct:
Final Answer: When \(x = 5\), the value of \(y\) is approximately \(9.3333\). Thus, the final answer is:
\(y \approx 9.3333\).
To solve for y in the equation \(3y + x = 33\):
1. Subtract \(x\) from both sides of the equation:
\[
3y = 33 - x
\]
2. Divide both sides by 3 to isolate \(y\):
\[
y = \frac{33 - x}{3}
\]
This can also be written as:
\[
y = \frac{33}{3} - \frac{x}{3} = 11 - \frac{x}{3}
\]
3. Now, substitute \(x = 5\) into the equation:
\[
y = \frac{33 - 5}{3} = \frac{28}{3} \approx 9.3333
\]
So your final answer is correct:
Final Answer: When \(x = 5\), the value of \(y\) is approximately \(9.3333\). Thus, the final answer is:
\(y \approx 9.3333\).
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