Question
What is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses
SA=12ab+3(12lb)
cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren
SA=a2+2aa24+h2−−−−−−√
cap s cap A is equal to A squared plus 2 A square root of the fraction with numerator A squared and denominator 4 plus h squared end root
SA=2(wl+lh+hw)
cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren
SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√
cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root
Remaining Attempts : 3
Responses
SA=12ab+3(12lb)
cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren
SA=a2+2aa24+h2−−−−−−√
cap s cap A is equal to A squared plus 2 A square root of the fraction with numerator A squared and denominator 4 plus h squared end root
SA=2(wl+lh+hw)
cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren
SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√
cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root
Remaining Attempts : 3
Answers
GPT-4o mini
The surface area (SA) of a regular triangular pyramid can be calculated using the formula:
\[ \text{SA} = \frac{3}{2} a s + \frac{\sqrt{3}}{4} a^2 \]
Where:
- \( a \) is the length of a side of the triangular base.
- \( s \) is the slant height of the pyramid.
Unfortunately, none of the provided options match this formula directly. If you have more options or further details, feel free to share!
\[ \text{SA} = \frac{3}{2} a s + \frac{\sqrt{3}}{4} a^2 \]
Where:
- \( a \) is the length of a side of the triangular base.
- \( s \) is the slant height of the pyramid.
Unfortunately, none of the provided options match this formula directly. If you have more options or further details, feel free to share!