Question

In a closed system, three objects have the following momentums: 110 kg⋅m/s
, −65 kg⋅m/s
, and −100 kg⋅m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

55 kg⋅m/s
55 kilograms times meters per second

275 kg⋅m/s
275 kilograms times meters per second

−55 kg⋅m/s
negative 55 kilograms times meters per second

−275 kg⋅m/s

Answer 1

To find the total momentum after the collision, we need to sum the momenta of the three objects.

The given momenta are:
- Object 1: \( 110 \, \text{kg⋅m/s} \)
- Object 2: \( -65 \, \text{kg⋅m/s} \)
- Object 3: \( -100 \, \text{kg⋅m/s} \)

Now, let’s calculate the total momentum:

\[
\text{Total Momentum} = 110 \, \text{kg⋅m/s} + (-65 \, \text{kg⋅m/s}) + (-100 \, \text{kg⋅m/s})
\]

Calculating this step by step:

1. \( 110 - 65 = 45 \, \text{kg⋅m/s} \)
2. \( 45 - 100 = -55 \, \text{kg⋅m/s} \)

So, the total momentum after the collision is \( -55 \, \text{kg⋅m/s} \).

The correct response is:
**−55 kg⋅m/s** (negative 55 kilograms times meters per second).