Asked by jennifer
I need help with this problem:
Dividing
7x^5y^5-21x^4y^4+14x^3y^3/7x^3y^3
Dividing
7x^5y^5-21x^4y^4+14x^3y^3/7x^3y^3
Answers
Answered by
drwls
If you mean
(7x^5y^5 -21x^4y^4 +14x^3y^3)/7x^3y^3 ,
the answer is
x^2y^2 - 3 xy + 2
Each of the three terms in the numerator gets divided by 7 x^3y^3.
(7x^5y^5 -21x^4y^4 +14x^3y^3)/7x^3y^3 ,
the answer is
x^2y^2 - 3 xy + 2
Each of the three terms in the numerator gets divided by 7 x^3y^3.
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