Asked by joe
What volume of .200M NaOH will be required to react completely with 32 mL of .15M HNO3
Answers
Answered by
DrBob222
mL x M = mL x M
Answered by
Lisa
Convert mL to L
(32ml)(1L/1000mL) = 0.032L
(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3
0.0048 mol = (.200M NaOH)(? L NaOH)
0.0048 / .200 = 0.024 L NaOH
0.024L (1000mL/1L) = 24ml NaOH
Good Luck with the rest of your Wiley Homework and hope this helps! :)
(32ml)(1L/1000mL) = 0.032L
(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3
0.0048 mol = (.200M NaOH)(? L NaOH)
0.0048 / .200 = 0.024 L NaOH
0.024L (1000mL/1L) = 24ml NaOH
Good Luck with the rest of your Wiley Homework and hope this helps! :)
Answered by
Lisa
Oh, and by the way, you didn't post the equation for this question, so my answer above is assuming that there is an equal amount moles for NaOH and HNO3.
Answered by
Anonymous
.018
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