Asked by joe

What volume of .200M NaOH will be required to react completely with 32 mL of .15M HNO3

Answers

Answered by DrBob222
mL x M = mL x M
Answered by Lisa
Convert mL to L
(32ml)(1L/1000mL) = 0.032L

(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3

0.0048 mol = (.200M NaOH)(? L NaOH)

0.0048 / .200 = 0.024 L NaOH

0.024L (1000mL/1L) = 24ml NaOH

Good Luck with the rest of your Wiley Homework and hope this helps! :)
Answered by Lisa
Oh, and by the way, you didn't post the equation for this question, so my answer above is assuming that there is an equal amount moles for NaOH and HNO3.
Answered by Anonymous
.018
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