Question
What volume of .200M NaOH will be required to react completely with 32 mL of .15M HNO3
Answers
DrBob222
mL x M = mL x M
Lisa
Convert mL to L
(32ml)(1L/1000mL) = 0.032L
(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3
0.0048 mol = (.200M NaOH)(? L NaOH)
0.0048 / .200 = 0.024 L NaOH
0.024L (1000mL/1L) = 24ml NaOH
Good Luck with the rest of your Wiley Homework and hope this helps! :)
(32ml)(1L/1000mL) = 0.032L
(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3
0.0048 mol = (.200M NaOH)(? L NaOH)
0.0048 / .200 = 0.024 L NaOH
0.024L (1000mL/1L) = 24ml NaOH
Good Luck with the rest of your Wiley Homework and hope this helps! :)
Lisa
Oh, and by the way, you didn't post the equation for this question, so my answer above is assuming that there is an equal amount moles for NaOH and HNO3.
Anonymous
.018