Question

Use​ left-to-right elimination to solve the system of equations.
left brace Start 3 By 1 Matrix 1st Row 1st Column 2nd Row 1st Column 3rd Row 1st Column EndMatrix

3 x plus 6 y minus 15 z
equals
12
4 x plus 7 y plus z
equals
52
x plus 6 y minus z
equals
36
Question content area bottom
Part 1
Select the correct choice below​ and, if​ necessary, fill in the answer boxes to complete the choice.
A.
The solution of the given system is xequals
  
enter your response here​, yequals
  
enter your response here​, and zequals
  
enter your response here.
​(Simplify your answers. Type integers or simplified​ fractions.)
B.
The system has infinitely many solutions. If z is any real​ number, then xequals
  
enter your response here and yequals
  
enter your response here.
​(Type expressions using z as the variable. Use integers or fractions for any numbers in the​ expression.)
C.
The system is inconsistent and has no solution.

Answers

Answered by GPT-4o mini
To solve the given system of equations using left-to-right elimination, we will rewrite the equations and eliminate variables step-by-step. The system is as follows:

1. \( 3x + 6y - 15z = 12 \) (Equation 1)
2. \( 4x + 7y + z = 52 \) (Equation 2)
3. \( x + 6y - z = 36 \) (Equation 3)

**Step 1: Eliminate \( z \) from Equations 2 and 3.**

From Equation 3, we can express \( z \) in terms of \( x \) and \( y \):

\[
z = x + 6y - 36
\]

Now, substitute this expression for \( z \) into Equations 1 and 2.

**Substituting into Equation 1:**

\[
3x + 6y - 15(x + 6y - 36) = 12
\]

Expanding this:

\[
3x + 6y - 15x - 90y + 540 = 12
\]

Combining like terms:

\[
-12x - 84y + 540 = 12
\]

Subtracting 540 from both sides:

\[
-12x - 84y = -528
\]

Dividing by -12:

\[
x + 7y = 44 \quad \text{(Equation 4)}
\]

**Substituting into Equation 2:**

\[
4x + 7y + (x + 6y - 36) = 52
\]

This simplifies to:

\[
4x + 7y + x + 6y - 36 = 52
\]

Combining like terms:

\[
5x + 13y - 36 = 52
\]

Adding 36 to both sides:

\[
5x + 13y = 88 \quad \text{(Equation 5)}
\]

**Step 2: Solve the new system of equations (Equations 4 and 5).**

From Equation 4:

\[
x + 7y = 44 \quad \text{(Equation 4)}
\]

From Equation 5:

\[
5x + 13y = 88 \quad \text{(Equation 5)}
\]

**Now solve this system:**

1. From Equation 4, express \( x \):

\[
x = 44 - 7y \quad \text{(Equation 6)}
\]

2. Substitute \( x \) from Equation 6 into Equation 5:

\[
5(44 - 7y) + 13y = 88
\]

Expanding:

\[
220 - 35y + 13y = 88
\]

Combining like terms:

\[
220 - 22y = 88
\]

Subtracting 220 from both sides:

\[
-22y = -132
\]

Dividing by -22:

\[
y = 6
\]

**Step 3: Substitute \( y \) back to find \( x \) and \( z \).**

Substituting \( y = 6 \) back into Equation 6:

\[
x = 44 - 7(6)
\]
\[
x = 44 - 42 = 2
\]

Now substitute \( x \) and \( y \) back into the expression for \( z \):

\[
z = x + 6y - 36
\]
\[
z = 2 + 6(6) - 36
\]
\[
z = 2 + 36 - 36
\]
\[
z = 2
\]

**Final Solution:**

Thus, the solution to the given system of equations is:

- \( x = 2 \)
- \( y = 6 \)
- \( z = 2 \)

**So the final answer is:**

A) The solution of the given system is \( x = 2 \), \( y = 6 \), and \( z = 2 \).

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