td= time down
ts=time for sound to come up
td+ts=15
depth= 1/2 g td^2
td= sqrt 2depth/g
ts= depth/343
15= depth/343 + sqrt 2depth/g
let x= sqrt depth
x^2= depth
solve the quadratic.
A stone is dropped into a deep canyon and is heard to strike the bottom 15s after release. How deep is the canyon? The speed of sound waves in air is 343 m/s and the acceleration of gravity is 9.8m/s^2. Answer in units of m.
2 answers
26