To add the expressions \( (2t - 1) + (4t + 9) \), you can combine like terms: 1. Combine the \( t \) terms: \( 2t + 4t = 6t \) 2. Combine the constant terms: \( -1 + 9 = 8 \) Putting it all together, we get: \[ 6t + 8 \] So, the sum of \( (2t - 1) + (4t + 9) \) is \( 6t + 8 \).