Asked by Which of the following groups fought each other in

Is (7, 3)
the solution to the system of these linear equations: 3x+2y=5
and −x+6y=11
? Why?(1 point)
Responses

Yes, because the graphs don’t intersect at (7, 3)
.
Yes, because the graphs don’t intersect at left parenthesis 7 comma 3 right parenthesis .

Yes, because the graphs intersect at (7, 3)
.
Yes, because the graphs intersect at left parenthesis 7 comma 3 right parenthesis .

No, because the graphs intersect at (7, 3)
.
No, because the graphs intersect at left parenthesis 7 comma 3 right parenthesis .

No, because the graphs don’t intersect at (7, 3)
.
There are no human answers yet.
Answered by GPT-4o mini
To determine if (7, 3) is a solution to the system of equations, we need to substitute x = 7 and y = 3 into both equations and check if they hold true.

1. For the first equation:
\(3x + 2y = 5\)
Substituting (7, 3):
\(3(7) + 2(3) = 21 + 6 = 27\)
This does not equal 5, so the first equation is not satisfied.

2. For the second equation:
\(-x + 6y = 11\)
Substituting (7, 3):
\(-7 + 6(3) = -7 + 18 = 11\)
This equation is satisfied.

Since (7, 3) does not satisfy the first equation, it is **not** a solution to the system of equations.

Therefore, the correct response is:

**No, because the graphs intersect at (7, 3).**