The average human heart beats about 3.5*10to the power of 7 times per year the current population of Massachusetts is about 7*10to the power of 6 about how many heartbeats occur in Massachusetts per year write the answer in scientific notation

To find the total number of heartbeats that occur in Massachusetts per year, we can multiply the average number of heartbeats per person per year by the population of Massachusetts.

1. The average number of heartbeats per person per year is \(3.5 \times 10^7\).
2. The population of Massachusetts is \(7 \times 10^6\).

Now, we can calculate the total heartbeats:

\[ \text{Total heartbeats} = (3.5 \times 10^7) \times (7 \times 10^6) \]

Now, we can multiply the coefficients (the numbers in front) and then add the exponents (the powers of 10):

\[ 3.5 \times 7 = 24.5 \]

For the powers of 10:

\[ 10^7 \times 10^6 = 10^{(7+6)} = 10^{13} \]

Combining both parts:

\[ \text{Total heartbeats} = 24.5 \times 10^{13} \]

Now, to express \(24.5\) in proper scientific notation, we convert it to \(2.45\) and adjust the exponent:

\[ 24.5 = 2.45 \times 10^1 \]

So,

\[ 24.5 \times 10^{13} = 2.45 \times 10^1 \times 10^{13} = 2.45 \times 10^{14} \]

Therefore, the total number of heartbeats that occur in Massachusetts per year is:

\[ \boxed{2.45 \times 10^{14}} \]