To transform the equation \( 8x + 2y = 6 \) from standard form to slope-intercept form (which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept), you can follow these steps:
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Isolate the \( y \) term: Start by moving the \( 8x \) to the other side of the equation. \[ 2y = -8x + 6 \]
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Divide by the coefficient of \( y \): In this case, divide every term by \( 2 \) to solve for \( y \). \[ y = -4x + 3 \]
The equation is now in slope-intercept form: \( y = -4x + 3 \).
So the selected steps are:
- Move \( 8x \) to the other side.
- Divide by \( 2 \).
Feel free to let me know if you need further assistance or additional details!