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Asked by Steve

prove (n choose k) = (n choose n-k)
7 years ago

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Answered by scott
it's a definition

nCk = n! / [k! * (n-k)!]

nC(n-k) = n! / {(n-k)! * [n - (n-k)]!}

n - (n-k) = k
7 years ago
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