A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75 - 16t2 where t is time in seconds

Answer 1

To find the number of feet the cliff-diver is above the ocean after 2 seconds, we can use the given formula:

$$h(t)=75-16t^2$$

where $h(t)$ is the height in feet after $t$ seconds.

Now, substitute $t=2$ into the formula:

$$h(2)=75-16(2^2)$$

Calculate $2^2$:

$$2^2=4$$

Now substitute this back into the equation:

$$h(2)=75-16(4)$$

Now, calculate $16\times 4$:

$$16\times 4=64$$

Now substitute this value back into the equation:

$$h(2)=75-64$$

Now, perform the subtraction:

$$h(2)=11$$

Therefore, the diver is 11 feet above the ocean after 2 seconds.