Question

A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75 - 16t2 where t is time in seconds

Answer 1

To find the number of feet the cliff-diver is above the ocean after 2 seconds, we can use the given formula:

\[
h(t) = 75 - 16t^2
\]

where \( h(t) \) is the height in feet after \( t \) seconds.

Now, substitute \( t = 2 \) into the formula:

\[
h(2) = 75 - 16(2^2)
\]

Calculate \( 2^2 \):

\[
2^2 = 4
\]

Now substitute this back into the equation:

\[
h(2) = 75 - 16(4)
\]

Now, calculate \( 16 \times 4 \):

\[
16 \times 4 = 64
\]

Now substitute this value back into the equation:

\[
h(2) = 75 - 64
\]

Now, perform the subtraction:

\[
h(2) = 11
\]

Therefore, the diver is 11 feet above the ocean after 2 seconds.